Contraception Costs
Rush's obscene comments are based either on a profound ignorance of how most woman-based contraception works, or on a profound cynicism about the American public's ignorance of how it works. Or (since we're talking about Rush, here) both.
I'm a computer scientist, so let me put it in computer science terms.
Cost of the most popular male-based contraceptives (i.e. condoms): O(n), where n is the number of sexual encounters. (Withdrawal not included.)
Cost of most female-based contraceptives (e.g. pill, IUD): O(1), with a large constant.
For non-computer scientists: to oversimplify somewhat, a function f(n) is O(n) if it is roughly proportional to n. In other words, as you increase n, you also increase f(n). A function f(n) is O(1) if it really doesn't matter how big n gets, it's always the same value. A good example of an O(n) function might be cost-of-gas-per-week as a function of number of miles driven. As the number of miles goes up, so does the amount I'm paying for gas (assuming prices don't drop). An example of an O(1) function: price-per-gallon as a function of the number of miles driven. It really doesn't matter how many miles I'm driving -- the cost per gallon remains the same.
Which brings me back to Rush. He thought he was being so clever with accusing Ms. Fluke of having so much sex that she couldn't afford to pay for it. Whereas for most forms of birth control that are fully in a woman's control (and I think that last bit is significant), it really doesn't matter whether you're getting it once an hour or (as primly as Rush or Rick could desire) conceding it once a year...the cost is the same. And it's jolly expensive, even for once a year.
Which is in stark contrast to the most popular male method: pay per use, and a fraction of the cost of the dinner/movie that precedes its use.
Why is that?
I guess I shouldn't be surprised that we're having this national conversation about who pays for birth control. Who wants to pay more to let women have control?
No comments:
Post a Comment